4x^2-53x+49=0

Solution for 4x^2-53x+49=0 equation:

4x^2-53x+49=0

a = 4; b = -53; c = +49;
Δ = b2-4ac
Δ = -532-4·4·49
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-45}{2*4}=\frac{8}{8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+45}{2*4}=\frac{98}{8}
=12+1/4
$